Here are some questions to go with the post on solving log equations. Answers and explanations are down at the bottom.
Find the exact value of x in each question: 2) log5x – log52 = 3 2) log2x – 2 = log23 3) log64(x + 1) = log64x + 1/2 4) 2log9(x – 3) = 4 5) log8(x + 1) = 1/3 – log8x
Answers below, scroll down…
.
.
.
.
.
.
.
.
.
.
.
.
.
.
1) log5x – log52 = 3 log5(x/2) = 3 x/2 = 53 = 125 x = 250 2) log2x – 2 = log23 log2x – log23 = 2 log2(x/3) = 2 x/3 = 22 = 4 x = 12 3) log64(x + 1) = log64x + 1/2 log64(x + 1) – log64x = 1/2 log64((x + 1)/x) = 1/2 (x + 1)/x = 641/2 = 8 x + 1 = 8x 7x = 1 x = 1/7 NOTE: "Exact answer" means leave your answer as a fraction unless it's an exact decimal. So 0.142857 would not be right. 4) 2log9(x – 3) = 4 log9(x – 3) = 2 (x – 3) = 92 = 81 x = 84 ALTERNATIVE METHOD: 4) 2log9(x – 3) = 4 log9(x – 3)2 = 4 (x – 3)2 = 94 (x – 3) = + or – 92 = +81 or –81 x = 84 orx = –78x = 84 because you can't have the log of a negative number 5) log8(x + 1) = 1/3 – log8x log8(x + 1) + log8x = 1/3 log8((x + 1)x) = 1/3 (x + 1)x = 81/3 = 2 x2 + x = 2 x2 + x - 2 = 0 (x + 2)(x – 1) = 0x = –2or x = 1 x = 1 because you can't have the log of a negative number